<aside> 📌 Quite unlike system in classical mechanics, measuring a quantum mechanical system alters its state in an irreversible way.

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Distiniguishing Quantum States & Measurement

OPEN SYSTEMS

CLOSED SYSTEMS

Projective Measurements

Now, let’s establish a few facts:

  1. Two projection operators $P_1$ & $P_2$ are orthogonal if their product is zero. That is, for every state $\ket{\psi}$ $P_1$ & $P_2$ are orthogonal if

    $P_1P_2\ket{\psi} = 0$

  2. A set of mutually exclusive measurement results corresponds to a set of orthogonal projection operators that act on the state space of the system. A complete set of orthogonal projection operators is one for which

    $\sum_i P_i = I$

  3. Every complete set of orthogonal projectors specifies a measurement that can be realized (at least one of the possible measurement results must be true ). The number of projection operators ($m$) is $\le$ dimension of the hilbert space that defines the system $d$, i.e.:

    $m \le d$

    for a qubit $\ket{\psi} = \alpha \ket{0} + \beta \ket{1}$, the projection operators corresponding to the mutually exclusive results $\ket{0}$ & $\ket{1}$ are:

    $\begin{matrix}P_0 = \ket{0}\bra{0} & P_1 = \ket{1}\bra{1} \end{matrix}$

  4. A given set of projection operators $\{P_1, P_2, P_3, \dots\}$ is said to be mutually orthogonal if:

    $P_iP_j = \delta_{ij}P_i$, where $\delta_{ij} = \left\{\begin{matrix}0, & \textrm{i != j} \\ 1, & \textrm{i = j}\end{matrix}\right.$

  5. Sum of two or more projection operators is a projection operator iff they are mutually orthogonal.

Probability of finding the ith outcome on measurement

Let, the dimension of the system be $n$, and consider a set of mutually orthogonal projection operators $\{P_1, P_2, P_3 \dots P_n\}$. Given, that the system is prepared in state $\ket{\psi}$, the probability of finding the ith outcome when a measurement is made, is given by: