m = (y2-y1) / (x2-x1)
mAB = (10-4) / (9- -3)
mAB = 6/12 = 1/2
mAD = (-4 - 4) / (1- -3)
mAD = -8/4 = -2
They -2 is the negative reciprocal of 1/2 and therefore the two lines are perpendicular to each other
6/12 = (2- -4) / (x-1)
6/12 = 6/x-1
1/2x -0.5 = 6
1/2x = 6.5
x = 13
d = √(x1-x2)^2 + (y1-y2)^2
= √(-3-9)^2 + (4-10)^2
= √144+36
= √180
= 6√5
m = (x1+x2) / 2 , (y1+y2) / 2
m = (1+9)/2 , (-4+10) / 2
= (5, 3)
6x + 3y = 12
y = 4 - 2x
6x + 8x + 4y = 19
14x + 4y = 19
14x + 4(4-2x) = 19
14x + 16 - 8x = 19
6x = 3
x = 1/2
6(1/2) + 3y = 12
3y = 12-3
3y = 9
y = 3
3+14+5+8+7+9+12+4 = 62km
ABDECBA
3+4+12+7+5+3 = 34km
log4 = 2log2
2log2/log2 = 2
log16 = 4log2
4log2/2log2 = 2
log1024 + log256 - log4 = t
10log2 + 8log2 - 2log2 = t
16log2 = t
t = log2^16
= log65,536
log2 + 2log2 + 4log2 + 8log2 + 16log2 + 32log2 = 63log2
b/sin60 = 3/sin105
b = sin60 (3/sin105)
b = 2.689
b = 2.69m
1
y = a(x-2)^2 + 1
2.6 = a(0-2)^2 +1
2.6 = 4a+1
4a = 1.6
a = 0.4
y = 0.4(x-2)^2 + 1
1.4 = 0.4(x-2)^2 + 1
0.4 = 0.4(x-2)^2
1 = x^2 - 2x + 4
x^2 - 2x + 3 = 0
(x+1)(x-3) = 0
x = -1 or x = 3
L = 3m
G’ C
does not have 2 red hair genes and do not have red hair