AC = AB + BC
BC = AC - AB
BC = (6/3) - (4/-0.5)
BC = (2/3.5)
AD = AC+CD
DC = -(8/-1)
AD = (6/3) + -(8/-1)
AD = -2/4
?
t+2c+b = 160
t+b-c = 70
t+2c+b = 160
-t-b+c = -70
3c = 90
c = 30
3/5
3/5 → 3/10, 2/3
(2/5) x (3/10) = 3/25
(3/5) x (2/3) = 2/5
(3/25) + (2/5) = 13/25
(3/25) / (13/25) = 3/13
3/25, 1/5
-2 = klog3 (10-1)
-2 = k log39
-2 = log3 3^2k
3^-2 = 3^2k
k = -1
d = fx-gx
d = log3 (5x+7) - -log3 (x-1)
d = log3 (5x+7)(x-1)
d = log3 (5x^2 - 5x + 7x - 7)
d = log3 (5x^2 +2x - 7)
d = log3 (5(4)^2 +2(4) - 7)
d = 4
0 = log3 (5x^2 +2x - 7)
1 = 5x^2 +2x - 7
5x^2 +2x - 8 = 0
(-b ± √b^2 - 4ac) / 2a
(-2 ± √2^2 - 4(5)(-8) / 2(5)
x = 1.08, 1.1
d = st
d = 500 x 2.33
d = 1,165 = 1170km
t = d/s
t = 5760/900
t = 6.4 x 60
t = 384