AOD = 92
DOB = 88
DCB = 44
Angle ADB is 90 because the angle at the centre is twice the angle at the circumference. Since the angle at a straight line at AOB is 180, ADB must be 90.
12^2 + 6^2 = x2
144 + 36 = x^2
180 = x^2
x = 6√5
A = pi r^2
A = pi (3√5)^2
= 45 pi
21/30
21/30 x 20/29 = 14/29
P ( A ∩ B) = P(A) x P(B)
21/175 = 85/175 X 30/175
0.12 ≠ 0.083
tan23 = P/x
x = P/tan23
P = x tan23
tan14 = P/(x+5)
x+5 = P/tan14
x = (P/tan14) -5
P = (x+5) tan14
x tan23 = (x+5) tan14